Maths Quiz on Sets Relations And Functions for IIT JEE & Engineering Exam

0

JEE Maths Quiz on Sets Relations And Functions

JEE Maths Quiz on Sets Relations And Functions : In this article you will get to Online test for JEE Main, JEE Advanced, UPSEE, WBJEE and other engineering entrance examinations that will help the students in their preparation. The Quiz on Sets Relations And Functions is free of cost and will useful in performance and inculcating knowledge.

Quiz on Sets Relations And Functions

 

Q1. If f (x) = cos (log x), then find the value of f (x) * f (4) − [1 / 2] * [f (x / 4) + f (4x)].
a) 16
b) 4
c) 0
d) 5

View Answer

c) 0

Solution:

f (x) = cos (log x)

Now let y = f (x) * f (4) − [1 / 2] * [f (x / 4) + f (4x)]

y = cos (log x) * cos (log 4) − [1 / 2] * [cos log (x / 4) + cos (log 4x)]

y = cos (log x) cos (log 4) − [1 / 2] * [cos (log x −log 4) + cos (log x + log 4)]

y = cos (log x) cos (log 4) − [1 / 2] * [2 cos (log x) cos (log 4)]

y = 0

Q2. If A = [(x, y) : x2 + y2 = 25] and B = [(x, y) : x2 + 9y2 = 144], then A ∩ B contains _______ points.
a) Two
b) Three
c) Four
d) Six

View Answer

c) Four

Solution:

A = Set of all values (x, y) : x2 + y2 = 25 = 52

B = [x2 / 144] + [y2 / 16] = 1

i.e., [x/ (12)2] + [y2 / (4)2] = 1.

Clearly, A ∩ B consists of four points.

Q3. Let f : R → R be defined by f (x) = 2x + |x|, then f (2x) + f (−x) − f (x) = _______.
a) 4|x|
b) 8|x|
c) 16|x|
d) 2|x|

View Answer

d) 2|x|

Solution:

f (2x) = 2 (2x) + |2x| = 4x + 2 |x|,

y = x2 + 1,

f (x) = 2x + |x|

f (2x) + f (−x) − f (x) = 4x + 2 |x| + |x| −2x − 2x − |x|

= 2|x|

Q4. If f (x) = cos [π2] x + cos[−π2] x, then find the function of the angle.
a) −1
b) 0
c) 1
d) 2

View Answer

a) −1

Solution:

f (x) = cos [π2] x + cos[−π2] x

f (x) = cos (9x) + cos (−10x)

= cos (9x) + cos (10x)

= 2 cos (19x / 2) cos (x / 2)

f (π / 2) = 2 cos (19π / 4) cos (π / 4);

f (π / 2) = 2 * −1 / √2 * 1/ √2

= −1

Q5. In a college of 300 students, every student reads 5 newspapers and every newspaper is read by 60 students. The number of newspapers is ________.
a) 25
b) 35
c) 30
d) 20

View Answer

a) 25

Solution:

Let the number of newspapers be x.

If every student reads one newspaper, the number of students would be x (60) = 60x

Since every student reads 5 newspapers, the number of students = [x * 60] / [5] = 300

x = 25

 

Syllabus and Previous Year Papers

Chemistry Syllabus for NEET & AIIMS Exams Click Here
Chemistry Syllabus for JEE Mains & Advanced Click Here
Chapter Wise NEET Chemistry Syllabus Click Here
Physics Syllabus for NEET & AIIMS Exams Click Here
Physics Syllabus for JEE Mains & Advanced Click Here
Chapter Wise NEET Physics Syllabus Click Here
Biology Syllabus for NEET & AIIMS Exams Click Here
Chapter Wise NEET Biology Syllabus Click Here
Maths Syllabus for JEE Mains & Advanced Click Here
Download NEET Previous Year Question Papers with Solution Click Here

 

Please Support us Like & Share Our Social Network

Facebook   https://www.facebook.com/ExamsRoadOfficial
Telegram  https://telegram.me/ExamsRoad
Twitter  https://twitter.com/ExamsRoad
Instagram https://www.instagram.com/ExamsRoad/
YouTube  Click Here To Subscribe Now

 

Thank You.

By TEAM ExamsRoad.com

ExamsRoad

LEAVE A REPLY

Please enter your comment!
Please enter your name here